Assignment inside Perl ternary conditional operator problems

Question :

Assignment inside Perl ternary conditional operator problems,

Answer :

This snippet of Perl code in my program is giving the wrong result.

$condition ? $a = 2 : $a = 3 ;  print $a;  

No matter what the value of $condition is, the output is always 3, how come?

,

This is explained in the Perl

Because of Perl operator precedence the statement is being parsed as

($condition ? $a= 2 : $a ) = 3 ;  

Because the ?: operator produces an assignable result, 3 is assigned to the result of the condition.

When $condition is true this means ($a=2)=3 giving $a=3

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When $condition is false this means ($a)=3 giving $a=3

The correct way to write this is

$a = ( $condition ? 2 : 3 );  print $a;  

We got bitten by this at work, so I am posting here hoping others will find it useful.

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Disclaimer :

The answers provided above are only to be used to guide the learning process. The questions above are open-ended questions, meaning that many answers are not fixed as above. I hope this article can be useful, Thank you

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